## The ratio test for series --- ## Ratio test #### Example $\sum\_{n=1}^\infty \frac{1}{2^n}$ converges. #### Proof The sequence of partial sums is $s_n = \frac12+\frac14+ \ldots+ \frac1{2^n}=\frac{1-(\frac12)^n}{1-\frac12} - 1 \to \frac1{1/2}-1=1$, as $n\to\infty$. □ --- ## Ratio test #### Example $\sum\_{n=1}^\infty \frac{1}{2^n}$ converges. #### Proof The sequence of partial sums is $s_n = \frac12+\frac14+ \ldots+ \frac1{2^n}=\frac{1-(\frac12)^n}{1-\frac12} - 1 \to \frac1{1/2}-1=1$, as $n\to\infty$. □ Here the ratio between consecutive terms is $\frac12$ and $0<\frac12<1$. The same argument would work for convergence of $\sum\_{n=1}^\infty r^n$ with any $r\in(-1,1)$. --- ## Ratio test #### Example $\sum\_{n=1}^\infty \frac{1}{2^n}$ converges. #### Proof The sequence of partial sums is $s_n = \frac12+\frac14+ \ldots+ \frac1{2^n}=\frac{1-(\frac12)^n}{1-\frac12} - 1 \to \frac1{1/2}-1=1$, as $n\to\infty$. □ Here the ratio between consecutive terms is $\frac12$ and $0<\frac12<1$. The same argument would work for convergence of $\sum\_{n=1}^\infty r^n$ with any $r\in(-1,1)$. But we can do better. #### Theorem The series $\sum\_{n=1}^\infty a_n$ with $\lim\_{n\to\infty} \left\lvert\frac{a\_{n+1}}{a_n}\right\rvert = \ell$ converges if $\ell<1$, but diverges if $\ell>1$. --- ## Ratio test #### Theorem The series $\sum\_{n=1}^\infty a_n$ with $\lim\_{n\to\infty} \left\lvert\frac{a\_{n+1}}{a_n}\right\rvert = \ell$ converges if $\ell<1$, but diverges if $\ell>1$. #### Examples $\sum\_{n=1}^\infty \frac1{3^n}$ converges, but $\sum\_{n=1}^\infty 2^n$ diverges. --- ## Ratio test #### Theorem The series $\sum\_{n=1}^\infty a_n$ with $\lim\_{n\to\infty} \left\lvert\frac{a\_{n+1}}{a_n}\right\rvert = \ell$ converges if $\ell<1$, but diverges if $\ell>1$. #### Examples $\sum\_{n=1}^\infty \frac1{3^n}$ converges, but $\sum\_{n=1}^\infty 2^n$ diverges. #### Examples Using the ratio test, and possibly some other tests, decide convergence of: $\sum\_{n=1}^\infty \frac{2^n}{3^n},\\; \sum\_{n=1}^\infty \frac{1}{n\sqrt n},\\; \sum\_{n=1}^\infty n\^{100}(\frac9{10})^n,\\; \sum\_{n=1}^\infty \frac{n\^{100}}{(\frac9{10})^n},\\; \sum\_{n=1}^\infty \frac{2^n + n^5}{n\sin(n) + 3^n},\\; \sum\_{n=1}^\infty \frac{2^n + 4n}{5 - 2^n}$